Question

What is the perimeter of a triangle with corners at `(7 ,2 )`, `(8 ,3 )`, and `(4 ,5 )`?

Answer 1

Perimeter is `10.1288`.

Explanation:

The formula for distance between two points `(x_1,y_1)` and `(x_2,y_2)` is `sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

Hence length of three sides will be given by

1. `sqrt((8-7)^2+(3-2)^2)=sqrt(1+1)=sqrt2=1.4142`
2. `sqrt((4-8)^2+(5-3)^2)=sqrt(16+4)=sqrt20=2sqrt5=2xx2.236=4.472`
3. `sqrt((4-7)^2+(5-2)^2)=sqrt(9+9)=3sqrt2=4.2426`

Hence perimeter is `1.4142+4.472+4.2426=10.1288`