What is the perimeter of a triangle with corners at #(8 ,5 )#, #(9 ,1 )#, and #(3 ,4 )#?

1 Answer
Jul 27, 2016

Perimeter is #15.930#

Explanation:

As perimeter is sum of all the sides, let us find all the sides of triangle formed by #(8,5)#, #(9,1)# and #(3,4)#. This will be surely distance between pair of points, (which is given by #sqrt((x_2-x_1)^2+(y_2-y_1)^2)#. Hence the three sides are:

#a=sqrt((9-8)^2+(1-5)^2)=sqrt(1+16)=sqrt17=4.123#

#b=sqrt((3-9)^2+(4-1)^2)=sqrt(36+9)=sqrt45=6.708# and

#c=sqrt((3-8)^2+(4-5)^2)=sqrt(25+1)=sqrt26=5.099#

Hence perimeter is #4.123+6.708+5.099=15.930#