What is the perimeter of the rectangle with length $5 a + 7 b$ $5a+7b$ and width $3 a + 5 b$ $3a+5b$ ?

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What is the perimeter of the rectangle with length $5 a + 7 b$ $5a+7b$ and width $3 a + 5 b$ $3a+5b$ ?

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Answer 1 · 2017-01-04T03:09:16

Perimeter of a rectangle is $= 16 a + 24 b$ $=16a+24b$

Explanation:

Length of the rectangle $= 5 a + 7 b$ $=5a+7b$
Width of the rectangle $= 3 a + 5 b$ $=3a+5b$

Perimeter of a rectangle is $= 2 (l + b)$ $=2(l + b)$

$= 2 [(5 a + 7 b) + (3 a + 5 b)]$ $=2[(5a+7b)+(3a+5b)]$

$= 2 [5 a + 7 b + 3 a + 5 b]$ $=2[5a+7b+3a+5b]$

$= 2 [8 a + 12 b]$ $=2[8a+12b]$

$= 16 a + 24 b$ $=16a+24b$

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What is the perimeter of the rectangle with length $5 a + 7 b$ $5a+7b$ and width $3 a + 5 b$ $3a+5b$ ?

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Explanation:

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What is the perimeter of the rectangle with length $5 a + 7 b$ $5a+7b$ and width $3 a + 5 b$ $3a+5b$ ?