What is the period and amplitude for #cos(pi/5)(x)#?

Question

6557 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-25T13:57:12

As below.

Standard form of cosine function is #y = A cos (Bx - C) + D#

Given #y = cos ((pi/5) x)#

#A = 1, B = pi/5, C = D = 0#

Amplitude #= |A| = 1#

Period #= (2 pi) / |B| = (2pi) / (pi/5) = 10#

Phase Shift #= -C / B = 0#

Vertical Shift #= D = 0#

graph{cos ((pi/5) x) [-10, 10, -5, 5]}