What is the period and amplitude for $y= -1/2cos(3x+4pi/3)$ ?

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Answer 1 · 2018-05-30T10:26:15

$Amplitude = |A| = 1/2$

Period $= (2pi) / |B| = (2pi) / 3$

Standard form of the cos function is $y = A cos (Bx - C) + D$

Given $y = (1/2) cos (3x + color(crimson)((4pi)/3))$

$A = 1/2, B = 3, C = (4pi)/3$

$Amplitude = |A| = 1/2$

Period $= (2pi) / |B| = (2pi) / 3$

Phase Shift $= -C / B = ((4pi)/3) / 3 = (4pi)/9$

Vertical Shift = D = 0#

What is the period and amplitude for y= -1/2cos(3x+4pi/3)y= -1/2cos(3x+4pi/3)?