What is the period of #f(t)=cos 5 t #?

1 Answer
Feb 13, 2016

#T=(2pi)/5=72^@#

Explanation:

For any general cosine function of the form #f(t)=AcosBt#, the amplitude is #A# and represents the maximum displacement from the t-axis, and the period is #T=(2pi)/B# and represents the number of units on the #t# axis for a complete cycle or wavelength of the graph to pass by.

So in this particular case, the amplitude is #1#, and the period is #T=(2pi)/5=72^@#,

since by the conversion factor, #360^@=2pirad#.

The graph is plotted below :

graph{cos(5x) [-2.735, 2.74, -1.368, 1.368]}