What is the period of $f(t)=cos ( ( 7 t ) / 2 )$ ?

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Answer 1 · 2016-05-16T06:52:51

$(4pi)/7$ .

The period for both sin kt and cos kt is (2pi)/k.

Here, k = = $7/2$ . So, the period is $4pi)/7.$ .

See below how it works

$cos ((7/2)(t+(4pi)/7))=cos((7t)/2+2pi)=cos((7t)/2)$

Answer 2 · 2016-05-16T07:53:52

$T=(4pi)/7$

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$y=A*cos(omega*t+phi)" general equation"$

$"A:Amplitude"$

$omega:"Angular velocity"$

$phi="phase angle"$

$"your equation:" f(t)=cos((7t)/2)$

$A=1$

$omega=7/2$

$phi=0$

$omega=(2pi)/T" T:Period"$

$7/2=(2pi)/T$

$T=(4pi)/7$

What is the period of f(t)=cos ( ( 7 t ) / 2 ) f(t)=cos ( ( 7 t ) / 2 ) ?