Question

What is the period of `f(t)=sin( ( 6 t) /7 +pi/4 )`?

Answer 1

`7pi/3`

Explanation:

The`sin (k(t+2npi/k)+l)=sin(kt+l)`, n=+-1.+-2,+-3,..,.
The value repeats when t is increased by `2pi/k`. This is the period.
Here, `k = 6/7`.
So, the period of f(t) is `7pi/3`..