What is the period of #f(x)=0.5sin(x)cos(x)#?

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Answer 1 · 2018-03-08T14:55:19

#Period = pi#

#f(x) = y = 0.5 sin x cos x#

#y = (1/2) (2sin x cos x) / 2#

#y = (1/4) sin 2x#

It’s in the form #y = a sin (bx + c) + d# where,

#a = 1/4, b = 2, c = d = 0#

Amplitude # = a = (1/4)#

Period # = (2pi) / |b| = (2pi) / 2 = pi#

graph{0.5 (sin (x) cos (x)) [-10, 10, -5, 5]}