What is the period of #y=3 cos 5x#?

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Answer 1 · 2014-10-06T02:56:14

The period is #omega=(2pi)/B# where #B# is the coefficient of the #x# term

period#=omega=(2pi)/B=(2pi)/5#

Enter the function after pressing the #Y=# button

Set the view to show x values from #0# to #(2pi)/5#

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The calculator changes #(2pi)/5# to its decimal equivalent.

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Then press the GRAPH to verify that we see a period of the cosine functions.

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