What is the period of #y=3 cos 5x#?

Question

7072 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-10-06T02:56:14

The period is #omega=(2pi)/B# where #B# is the coefficient of the #x# term

period#=omega=(2pi)/B=(2pi)/5#

Enter the function after pressing the #Y=# button

Set the view to show x values from #0# to #(2pi)/5#

enter image source here

The calculator changes #(2pi)/5# to its decimal equivalent.

enter image source here

Then press the GRAPH to verify that we see a period of the cosine functions.

enter image source here