What is the pH of $10^{- 2}$ $10^(-2)$ $M HCl$ $"M HCl"$ solution?

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What is the pH of $10^{- 2}$ $10^(-2)$ $M HCl$ $"M HCl"$ solution?

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Answer 1 · 2018-04-06T00:54:50

$2$ $2$

Explanation:

Because

$[H^{+}] = 10^{- pH}$ $["H"^(+)]= 10^-"pH"$

Therefore, the exponent of $10$ $10$ is the pH and this makes sense because the $pH$ $"pH"$ $(2)$ $(2)$ is less than $7$ $7$ , which indicates that it should be an acid. This is true because $HCl$ $"HCl"$ is a strong acid, i.e.

$[H^{+}] = [HCl]$ $["H"^(+)] = ["HCl"]$

Answer 2 · 2018-04-06T11:33:37

$2$ $2$

Explanation:

Hydrochloric acid is a strong acid which dissociates into single hydrogen $(H^{+})$ $(H^+)$ ions in an aqueous solution.

The $pH$ $"pH"$ of a solution is given by the equation,

$pH = - log [H^{+}]$ $"pH"=-log[H^+]$

$[H^{+}]$ $[H^+]$ is the hydrogen ion concentration in terms of molarity

And so, we got:

$pH = - log [10^{- 2}]$ $"pH"=-log[10^-2]$

$= 2$ $=2$

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What is the pH of $10^{- 2}$ $10^(-2)$ $M HCl$ $"M HCl"$ solution?

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