What is the pH of $2.34 * 10^-5$ $NaOH$ solution?

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Answer 1 · 2018-06-26T05:12:28

Well, we know that $pH+pOH=14$ in water...

And $[HO^-]2.34xx10^-5*mol*L^-1$ ...

$pOH=-log_10[HO^-]=-log_10(2.34xx10^-5)=4.63$

$pH=14-pH=13-4.63=9.37.$ ...the solution is slightly basic...

What is the pH of 2.34 * 10^-52.34 * 10^-5 NaOHNaOH solution?