Question

What is the pH of `2.34 * 10^-5` `NaOH` solution?

Answer 1

Well, we know that `pH+pOH=14` in water...

Explanation:

And `[HO^-]2.34xx10^-5*mol*L^-1`...

`pOH=-log_10[HO^-]=-log_10(2.34xx10^-5)=4.63`

`pH=14-pH=13-4.63=9.37.`...the solution is slightly basic...