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What is the pH of a 0.027 M KOH solution?

1 Answer

May 2, 2017

We use the relationship $p H + p O H = 14$ $pH+pOH=14$ , .........and get $p H = 12.4$ $pH=12.4$

Explanation:

$p H = - {log}_{10} [H_{3} O^{+}]$ $pH=-log_(10)[H_3O^+]$ , and $p O H = 14 - p H$ $pOH=14-pH$

And thus...........

$p H = 14 - p O H$ $pH=14-pOH$

$p H = 14 - (- {log}_{10} (0.027))$ $pH=14-(-log_(10)(0.027))$

$p H = 14 - (1.57) = 12.4$ $pH=14-(1.57)=12.4$ .

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