Question

What is the pH of a 0.027 M KOH solution?

Answer 1

We use the relationship `pH+pOH=14`, .........and get `pH=12.4`

Explanation:

`pH=-log_(10)[H_3O^+]`, and `pOH=14-pH`

And thus...........

`pH=14-pOH`

`pH=14-(-log_(10)(0.027))`

`pH=14-(1.57)=12.4`.