What is the pH of a 0.35 M $N H_{4} C l$ $NH_4Cl$ solution?

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What is the pH of a 0.35 M $N H_{4} C l$ $NH_4Cl$ solution?

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Answer 1 · 2016-06-11T21:14:48

And what is $p K_{a}$ $pK_a$ for $ammonium chloride$ $"ammonium chloride"$ ?

Explanation:

For the reaction:

$N H_{4}^{+} + H_{2} O (l) ⇌ N H_{3} (a q) + H_{3} O^{+}$ $NH_4^+ + H_2O(l) rightleftharpoons NH_3(aq) + H_3O^+$

$K_{a}$ $K_a$ $=$ $=$ $\frac{[N H_{3} (a q)] [H_{3} O^{+}]}{[N H_{4}^{+}]}$ $([NH_3(aq)][H_3O^+])/([NH_4^+])$

$K_{a}$ $K_a$ $=$ $=$ $\frac{x^{2}}{0.35 - x}$ $x^2/(0.35-x)$ , where $x$ $x$ $=$ $=$ $[H_{3} O^{+}]$ $[H_3O^+]$ $=$ $=$ $[N H_{3}]$ $[NH_3]$

$p H$ $pH$ $=$ $=$ $- {log}_{10} [H_{3} O^{+}]$ $-log_10[H_3O^+]$ may be solved exactly, once we have details of $K_{a}$ $K_a$ . And $K_{a}$ $K_a$ $=$ $=$ $? ? ?$ $???$

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What is the pH of a 0.35 M $N H_{4} C l$ $NH_4Cl$ solution?

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