Question

What is the pH of a `5.00 x 10^-2` M aqueous solution of `Ba(OH)_2`?

Answer 1

`pH=13`

Explanation:

We know that in water under standard conditions, `pH+pOH=14`.

Now for `5.00xx10^-2*mol*L^-1` `Ba(OH)_2`, `[HO^-]=0.100*mol*L^-1`; and thus `pOH=-log_10[HO^-]` `=-log_10(10^-1)=1`. And thus `pH=13`.

For another example see [this linky.](https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871)