What is the pOH of 2.15 M $Ba(OH)_2$ solution? Is the solution neutral, acidic, or basic?

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Answer 1 · 2016-05-08T08:56:19

$pOH$ $=$ $-log_(10)[HO^-]$ $=$ $??$

Given $2.15*mol*L^-1$ barium hydroxide, $[HO^-]$ $=$ $4.30*mol*L^-1$

$pOH$ $=$ $-log_(10)[HO^-]$ $=$ $-log_(10){4.30}$ $=$ $-0.63$ .

The solution is strongly basic.

What is the pOH of 2.15 M Ba(OH)_2Ba(OH)_2 solution? Is the solution neutral, acidic, or basic?