What is the polar form of #( -4,27 )#?

1 Answer
Nov 9, 2016

#(27.29,1.72)#

Explanation:

The polar form is #(r,theta)#
To find r use the formula #r^2=x^2+y^2#

#r=sqrt((-4)^2+27^2)~~27.29#

To find #theta# use the formula #tan theta =y/x# but make sure you look at the quadrant that the point is in to determine the right #theta# using the rules for the quadrants

#tan theta = 27/-4#

#theta=tan^-1(27/-4)~~-1.423717971# but the point is in quadrant two so we add #pi#. Note that #theta# is usually in radian.

Hence, #theta ~~ 1.72#