What is the projection of <2,-5,1 > onto <6,-8,3 >?

1 Answer
Dec 4, 2016

The answer is =55/109〈6,-8,3〉

Explanation:

The projection of vecb onto veca is

=(veca.vecb)/(∥veca∥^2)veca

Here, vecb=〈2,-5,1〉 and veca=〈6,-8,3〉

The dot product is

veca.vecb=〈2,-5,1〉.〈6,-8,3〉=(12+40+3)=55

The modulus of veca=∥〈6,-8,3〉∥=sqrt(36+64+9)=sqrt109

The projection is

=55/109〈6,-8,3〉