What Is the quotient of $(x^{3} + 6 x^{2} + 11 x + 6) \div (x^{2} + 4 x + 3)$ $(x^3 + 6x^2 + 11x + 6) -: (x^2 + 4x + 3)$ ?

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Answer 1 · 2018-03-03T01:53:15

Quotient is $x + 2$ $x+2$

$x^{3} + 6 x^{2} + 11 x + 6$ $x^3+6x^2+11x+6$

= $x^{3} + 4 x^{2} + 3 x + 2 x^{2} + 8 x + 6$ $x^3+4x^2+3x+2x^2+8x+6$

= $x \cdot (x^{2} + 4 x + 3) + 2 \cdot (x^{2} + 4 x + 3)$ $x*(x^2+4x+3)+2*(x^2+4x+3)$

= $(x^{2} + 4 x + 3) \cdot (x + 2)$ $(x^2+4x+3)*(x+2)$

Hence quotient is $x + 2$ $x+2$

What Is the quotient of (x3+6x2+11x+6)÷(x2+4x+3)(x^3 + 6x^2 + 11x + 6) -: (x^2 + 4x + 3)?