What is the range of $sqrt (4-x^2)$ ?

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Answer 1 · 2017-12-28T07:01:05

${yinRR|0<=y<=2}$

I find it is most helpful to solve the domain over which the function exists.

In this case $4-x^2>=0$ which means $-2<=x<=2$

On this domain, the smallest value the function can take is zero and the largest value it can take is $sqrt(4)=2$

Hence, the the range of the function is ${yinRR|0<=y<=2}$

Hope this helps :)

What is the range of sqrt (4-x^2)sqrt (4-x^2)?