What is the range of the function #f(x)=2/(x+3) -4#?
1 Answer
Apr 30, 2017
Explanation:
#"Rearrange f(x) to make x the subject"#
#y=f(x)=2/(x+3)-(4(x+3))/(x+3)#
#rArry=(2-4x-12)/(x+3)=(-4x-10)/(x+3)#
#color(blue)"cross-multiply"#
#rArryx+3y=-4x-10#
#rArryx+4x=-10-3y#
#rArrx(y+4)=-10-3y#
#rArrx=(-10-3y)/(y+4)# The denominator cannot be zero as this would make the function
#color(blue)"undefined".# Equating the denominator to zero and solving gives the value that y cannot be.
#"solve "y+4=0rArry=-4larrcolor(red)" excluded value"#
#"range " y inRR,y!=-4#