Question

What is the range of the function `sqrt(2x-8)`?

Answer 1

Range `>=0`

Explanation:

There are two rules about square roots:
(1)
The argument must be non-negative, or `2x-8>=0`
This means the domain is restricted to `x>=4`
(2)
The function has a non-negative outxome. Since everything down to `0` is possible (when `x=4`) the range is `>=0`