What is the ratio of the moles of conjugate base to the moles of acid if the pH is 5.29 and the pKa is 5.150?

1 Answer
anor277
Nov 5, 2016

#[[A^-]]/[[HA]]=10^(0.14)# #=# #??#

Explanation:

#pH=pK_a + log_10([[A^-]]/[[HA]])#

i.e. #5.29=5.150 + log_10([[A^-]]/[[HA]])#

Thus #log_10([[A^-]]/[[HA]])=0.14#.

#[[A^-]]/[[HA]]=10^(0.14)# #=# #??#

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