What is the reference angle when theta is -1.8? and Why?

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What is the reference angle when theta is -1.8? and Why?

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Answer 1 · 2018-01-07T21:43:09

The reference angle is always $0^{o}$ $0^o$ by default.

Explanation:

If not otherwise specified, the standard reference for angles is always $0^{o}$ $0^o$ (E or x-axis) $\Rightarrow 90^{o}$ $rArr 90^o$ is N, $180^{o} W, 270^{o} S$ $180^o W, 270^o S$ .

If theta is expressed as - ${1.8}^{o}$ $1.8^o$ without giving any other reference, then it is ${1.8}^{o}$ $1.8^o$ clockwise from the East (or x-axis) by default.

BTW, is theta - ${1.8}^{o}$ $1.8^o$ or -1.8 radians?

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What is the reference angle when theta is -1.8? and Why?

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Explanation:

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