What is the relationship between the pOH and the OH- ion concentration of a solution?

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What is the relationship between the pOH and the OH- ion concentration of a solution?

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Answer 1 · 2016-12-16T17:35:39

$p O H = - {log}_{10} [H O^{-}]$ $pOH=-log_10[HO^-]$

Explanation:

And in aqueous solution, the acid base equilibrium operates:

$2 H_{2} O ⇌ H_{3} O^{+} + H O^{-}$ $2H_2OrightleftharpoonsH_3O^(+) + HO^-$

At $298 \cdot K$ $298*K$ , $K_{w} = 10^{- 14} = [H O^{-}] [H_{3} O^{+}]$ $K_w=10^-14=[HO^-][H_3O^+]$

And taking negative ${log}_{10}$ $log_10$ of both sides.............

$- {log}_{10} K_{w} = - {log}_{10} 10^{- 14} = - {log}_{10} [H O^{-}] - {log}_{10} [H_{3} O^{+}]$ $-log_10K_w=-log_(10)10^-14=-log_10[HO^-]-log_10[H_3O^+]$

i.e. $14 = p H + p O H$ $14=pH+pOH$ .

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What is the relationship between the pOH and the OH- ion concentration of a solution?

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