What is the second derivative of #f(t) = (3e^-2t) - (5e^-t) #?

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Answer 1 · 2018-08-05T10:58:43

#(d^2y)/(dt^2) = - 5/ e^t#

#f(t) = (3 e^(-2)t) - (5 e^(-t))# or

#f(t) = (3/ e^2 t) - (5 e^(-t))# or

#f^'(t) = (3/ e^2 ) - (5 e^(-t)*(-1))# or

#f^'(t) = (3/ e^2 ) + (5 e^(-t))# or

#(d^2y)/(dt^2) = 0 + (5 e^(-t)*(-1))# or

#(d^2y)/(dt^2) = - (5 e^(-t))# or

#(d^2y)/(dt^2) = - 5/ e^t# [Ans]