What is the second derivative of $f(t) = (3e^-2t) - (5e^-t)$ ?

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Answer 1 · 2018-08-05T10:58:43

$(d^2y)/(dt^2) = - 5/ e^t$

$f(t) = (3 e^(-2)t) - (5 e^(-t))$ or

$f(t) = (3/ e^2 t) - (5 e^(-t))$ or

$f^'(t) = (3/ e^2 ) - (5 e^(-t)*(-1))$ or

$f^'(t) = (3/ e^2 ) + (5 e^(-t))$ or

$(d^2y)/(dt^2) = 0 + (5 e^(-t)*(-1))$ or

$(d^2y)/(dt^2) = - (5 e^(-t))$ or

$(d^2y)/(dt^2) = - 5/ e^t$ [Ans]

What is the second derivative of f(t) = (3e^-2t) - (5e^-t) f(t) = (3e^-2t) - (5e^-t) ?