Question

What is the second derivative of `f(x)=15x^3-23x^2+9x-1`?

Answer 1

`f''(x)=90x-46`

Explanation:

The main thing to know here is that `d/dx[x^n]=nx^(n-1)`.

`f(x)=15x^3-23x^2+9x-1`

`f'(x)=45x^2-46x+9`

`f''(x)=90x-46`