Question

What is the second derivative of `f(x)= 8/x-2x^3`?

Answer 1

`f''(x)=16/x^3-12x`

Explanation:

`"differentiate using the "color(blue)"power rule"`

`•color(white)(x)d/dx(ax^n)=nax^(n-1)`

`f(x)=8/x-2x^3=8x^-1-2x^3`

`f'(x)=-8x^-2-6x^2`

`f''(x)=16x^-3-12x=16/x^3-12x`