What is the second derivative of f(x)=csc(3x^2-x)f(x)=csc(3x2−x)? Calculus Graphing with the Second Derivative Relationship between First and Second Derivatives of a Function 1 Answer Timber Lin Mar 3, 2018 f'(x) = -csc(3x^2-x)cot(3x^2-x) * (6x-1) Explanation: f(x) = csc(3x^2-x) f'(x) = -csc(3x^2-x)cot(3x^2-x) * d/dx(3x^2-x) (cscx derivative and chain rule ) f'(x) = -csc(3x^2-x)cot(3x^2-x) * (6x-1) derivative of csc(x): csc(x) = 1/sin(x) d/dx(csc(x)) = d/dx(1/sin(x)) =(sin(x)d/dx(1)-1(d/dx(sin(x))))/(sin^2(x)) =(sin(x)(0)-(cos(x)))/(sin^2(x)) =(-(cos(x)))/(sin^2(x)) =-1/sin(x) * cos(x)/sin(x) =-csc(x)cot(x) Answer link Related questions What is the relationship between the First and Second Derivatives of a Function? Question #64fc4 What are the first two derivatives of y = 2sin(3x) - 5sin(6x)? What is the second derivative of the function f(x)=sec x? If f(x)=sec(x), how do I find f''(π/4)? What is the second derivative of g(x) = sec(3x+1)? How do you use the second derivative test to find the local maximum and minimum for... What is the first and second derivative of 1/(x^2-x+2)? What is the second derivative of x/(x-1) and the first derivative of 2/x? What does the 2nd Derivative Test tell you about the behavior of f(x) = x^4(x-1)^3 at these... See all questions in Relationship between First and Second Derivatives of a Function Impact of this question 2362 views around the world You can reuse this answer Creative Commons License