What is the silver carbonate formula?

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What is the silver carbonate formula?

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Answer 1 · 2018-06-01T18:23:21

Well, silver commonly forms a $A g^{+}$ $Ag^+$ cation....

Explanation:

And when it makes music with carbonate anion...

$2 A g^{+} + C O_{3}^{2 -} \to A g_{2} C O_{3} (s) ⏐ ⏐ ↓$ $2Ag^+ + CO_3^(2-) rarr Ag_2CO_3(s)darr$

Wikipedia says that $K_{sp} = 8.46 \times 10^{- 12}$ $K_"sp"=8.46xx10^-12$ for $silver carbonate...$ $"silver carbonate..."$ ... under standard conditions, and we can use this value to assess the solubility of silver carbonate...

$A g_{2} C O_{3} (s) H_{2} O - - \to 2 A g^{+} + C O_{3}^{2 -}$ $Ag_2CO_3(s) stackrel(H_2O)rarr2Ag^+ + CO_3^(2-)$ ...

...for which $K_{sp} = {[A g^{+}]}^{2} [C O_{3}^{-}]$ $K_"sp"=[Ag^+]^2[CO_3^(-)]$

And given the equation.... $[A g^{+}] = 2 S; [C O_{3}^{2 -}] = S$ $[Ag^+]=2S; [CO_3^(2-)]=S$ ...

And so $K_{sp} = {(2 S)}^{2} S = 4 S^{3}$ $K_"sp"=(2S)^2S=4S^3$

And (finally) $S_{solubility of silver carbonate} =^{3} \sqrt{\frac{8.46 \times 10^{- 12}}{4}} = 1.28 \times 10^{- 4} \cdot m o l \cdot L^{- 1}$ $S_"solubility of silver carbonate"=""^(3)sqrt((8.46xx10^-12)/(4))=1.28xx10^-4*mol*L^-1$

A solubility in ……………………………. $g \cdot L^{- 1} = 1.28 \times 10^{- 4} \cdot m o l \cdot L^{- 1} \times 275.81 \cdot g \cdot m o l^{- 1} = 35 \cdot m g \cdot L^{- 1}$ $g*L^-1=1.28xx10^-4*mol*L^-1xx275.81*g*mol^-1=35*mg*L^-1$ ...

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What is the silver carbonate formula?

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