What is the simplest formula for copper (II) and nitride?

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Answer 1 · 2016-10-28T04:34:14

$C u_{3} N_{2}$ $Cu_"3"N_"2"$

The easiest way of thinking about the combination of ions is by using the method I recall as being called , "the swap and drop"

So we have two ions,

$C u^{2 +}$ $Cu^(2+)$ and $N^{3 -}$ $N^(3-)$

now we swap the charge of each and drop, Note that the two ions have to be of opposite charge.

$C u_{3}$ $Cu_"3"$ and $N_{2}$ $N_2$

Now combine,

$C u_{3} N_{2}$ $Cu_"3"N_"2"$

This is the simplest formula.