What is the size of the force of gravity between the Earth with a mass of 5.98 x 10^141014 and the Sun that has a mass of 1.99 x 10^301030 if the distance separating the earth and the sun is 1.50x10^111011 m ?

1 Answer
A08
Mar 12, 2017

As per Law of Universal Gravitation the force of attraction F_GFG between two bodies of masses M_1 and M_2M1andM2 located at a distance distance rr from each other is given as

F_G =G (M_1.M_2)/r^2FG=GM1.M2r2 .......(1)

Where GG is the proportionality constant.
It has the value 6.67408 xx 10^-11 m^3 kg^-1 s^-26.67408×10−11m3kg−1s−2

Inserting given values we get
F_G =6.67408 xx 10^-11 xx(5.98 xx 10^24xx1.99 xx 10^30)/(1.50xx10^11)^2FG=6.67408×10−11×5.98×1024×1.99×1030(1.50×1011)2
=>F_G =3.53 xx 10^22N⇒FG=3.53×1022N
.-.-.-.-.-.-.-.-.-

There appears to be typo error in writing mass of earth. In the calculations this has been corrected.

Related questions
See all questions in Newton's Law of Gravitation
Impact of this question
2375 views around the world
You can reuse this answer
Creative Commons License