What is the slope and intercept for $y = \frac{1}{2} x - 1$ $y=1/2x-1$ and how would you graph it?

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What is the slope and intercept for $y = \frac{1}{2} x - 1$ $y=1/2x-1$ and how would you graph it?

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Answer 1 · 2015-10-10T13:08:06

Slope = $\frac{1}{2}$ $1/2$ , intercept = $- 1$ $-1$ . For the graph, see below.

Explanation:

When a line's equation is in the form $y = m x + q$ $y=mx+q$ , then $m$ $m$ is the slope, and $q$ $q$ is the $y$ $y$ -intercept.

So, in your case, $m = \frac{1}{2}$ $m=1/2$ is the slope, and $q = - 1$ $q=-1$ is the intercept.

The easiest way to graph a line is always to find two of its point and connecting them. For example, let's pick $x = 0$ $x=0$ and $x = 2$ $x=2$ . The correspondant $y$ $y$ values are

$y (0) = \frac{1}{2} \cdot 0 - 1 = - 1$ $y(0) = 1/2*0 - 1 = -1$ , and

$y (2) = \frac{1}{2} \cdot 2 - 1 = 1 - 1 = 0$ $y(2) = 1/2*2-1 = 1-1 = 0$ .

So, the line passes through $(0, - 1)$ $(0,-1)$ and $(2, 0)$ $(2,0)$ , and with two points known, the line is uniquely identified.

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What is the slope and intercept for $y = \frac{1}{2} x - 1$ $y=1/2x-1$ and how would you graph it?

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What is the slope and intercept for $y = \frac{1}{2} x - 1$ $y=1/2x-1$ and how would you graph it?