What is the slope and intercept of $10 y = 5 x + 20$ $10y = 5x + 20$ ?

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Answer 1 · 2016-06-30T16:59:33

Slope is $\frac{1}{2}$ $1/2$ and intercept on $y$ $y$ -axis is $2$ $2$

The slope intercept form of the equation of a line is

$y = m x + c$ $y=mx+c$ , where $m$ $m$ is the slope of line and $c$ $c$ is intercept on $y$ $y$ -axis

As $10 y = 5 x + 20$ $10y=5x+20$

$\Leftrightarrow y = \frac{5}{10} x + \frac{20}{10}$ $hArry=5/10x+20/10$ or $y = \frac{1}{2} x + 2$ $y=1/2x+2$

Hence Slope is $\frac{1}{2}$ $1/2$ and intercept on $y$ $y$ -axis is $2$ $2$ .

What is the slope and intercept of 10y=5x+2010y = 5x + 20?