What is the slope and intercept of #5x-2y = 10#?

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Answer 1 · 2018-05-07T07:36:59

#m = 5/2 and c = -5#

You need to change the equation into the form #y = mx+c#

#5x-2y = 10" "larr# make the #y# term positive,

#5x-10 = 2y" "larr div 2#

#5/2x-5=y#

or, #y= 5/2x-5" "larr# this is slope-intercept form

In #y = color(blue)(m)x color(red)(+c)#

#color(blue)(m)# gives the slope and #color(red)(+c)# is the y-intercept

#m = color(blue)(5/2) and c = color(red)(-5)#