What is the slope and the y intercept of the line defined by the equation $3 x - 4 y = 5$ $3x-4y=5$ ?

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Answer 1 · 2016-12-16T15:11:56

$y = \frac{3}{4} x - \frac{5}{4}$ $y = 3/4x - 5/4$

The slope-intercept form of a linear equation is:

$y = m x + b$ $color(red)(y = mx + b)$
Where $m$ $m$ is the slope and $b$ $b$ is the y-intercept value.

Therefore, we must solve this standard form linear equation for $y$ $y$ to obtain the slope-intercept form:

$3 x - 3 x - 4 y = - 3 x + 5$ $3x - 3x - 4y = -3x + 5$

$0 - 4 y = - 3 x + 5$ $0 - 4y = -3x + 5$

$- 4 y = - 3 x + 5$ $-4y = -3x + 5$

$\frac{- 4 y}{- 4} = \frac{- 3 x + 5}{- 4}$ $(-4y)/-4 = (-3x + 5)/-4$

$(cancel(-4)y)/cancel(-4) = (-3x)/-4 + 5/-4$

$y = 3/4x - 5/4$

What is the slope and the y intercept of the line defined by the equation 3x-4y=53x−4y=53x-4y=5?