What is the slope for (2, 3)and (-3, 0)?

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Answer 1 · 2018-03-23T13:32:46

The slope is $\frac{3}{5}$ $3/5$ ,

The slope of a linear line in the form of $y = m x + b$ $y=mx+b$ , is $m$ $m$ , and is found by:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

Note that $(x_{1}, y_{1}), (x_{2}, y_{2})$ $(x_1,y_1),(x_2,y_2)$ are the two coordinates.

Here, I'll pick $(x_{1}, y_{1}) = (2, 3)$ $(x_1,y_1)=(2,3)$ , $(x_{2}, y_{2}) = (- 3, 0)$ $(x_2,y_2)=(-3,0)$ .

And so, the slope will be,

$m = \frac{0 - 3}{- 3 - 2}$ $m=(0-3)/(-3-2)$

$= \frac{- 3}{- 5}$ $=(-3)/(-5)$

$= \frac{3}{5}$ $=3/5$