What is the slope-intercept form of the line passing through $(0, 6)$ $(0, 6)$ and $(- 4, 1)$ $(-4, 1)$ ?

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Answer 1 · 2016-09-07T01:58:57

y = 5/4x + 6

y = mx + b.

The b equals the y intercept, which is the place where x =0. The y-intercept is the place where the line "begins" on the y axis.

For this line it is easy to find the y intercept because one given point is (0,6) This point is the y intercept. So b = 6

m = the slope of the line, ( think m = mountain slope) The slope is the angle of the line.

The slope = $\frac{y_{1} - y_{2}}{x_{1} - x_{2}}$ $( y_1 - y_2)/( x_1 - x_2)$

Substitute the values of the points given in the problem

m = $\frac{6 - 1}{0 - (- 4)}$ $( 6-1)/ (0-(-4))$ = 5/4

Now we have m and b.

#y = 5/4x+6

What is the slope-intercept form of the line passing through (0,6) (0, 6) and (−4,1) (-4, 1) ?