What is the slope-intercept form of the line passing through (-2, -1)(−2,−1) and (-1, 7) (−1,7)?

1 Answer
Johnson Z.
Dec 17, 2015

y=8x+15y=8x+15

Explanation:

The slope-intercept form of a line can be represented by the equation:

y=mx+by=mx+b

Start by finding the slope of the line, which can be calculated with the formula:

m=(y_2-y_1)/(x_2-x_1)m=y2−y1x2−x1

where:
m=m=slope
(x_1, y_1)=(-2, -1)(x1,y1)=(−2,−1)
(x_2, y_2)=(-1, 7)(x2,y2)=(−1,7)

Substitute your known values into the equation to find the slope:

m=(y_2-y_1)/(x_2-x_1)m=y2−y1x2−x1

m=(7-(-1))/(-1-(-2))m=7−(−1)−1−(−2)

m=8/1m=81

m=8m=8

So far, our equation is y=8x+by=8x+b. We still need to find bb, so substitute either point, (-2,-1)(−2,−1) or (-1,7)(−1,7) into the equation since they are both points on the line, to find bb. In this case, we will use (-2,-1)(−2,−1):

y=8x+by=8x+b

-1=8(-2)+b−1=8(−2)+b

-1=-16+b−1=−16+b

b=15b=15

Substitute the calculated values to obtain the equation:

y=8x+15y=8x+15

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