What is the slope-intercept form of the line passing through (3,0) and (−4,1)?

3 Answers
Harish Chandra Rajpoot
Jul 18, 2018

y=−17x+37

Explanation:

The equation of straight line passing through the points (x1,y1)≡(3,0) & (x2,y2)≡(−4,1) is given as follows

y−y1=y2−y1x2−x1(x−x1)

y−0=1−0−4−3(x−3)

y=−17(x−3)

y=−17x+37

Above equation of line is the slope-intercept form: y=mx+c

Cem Sentin
Jul 18, 2018

y=−17⋅x+37

Explanation:

After using slope formula for known 2 points,

m=1−0−4−3=1−7=−17

After using formula for known slope and a point,

y−0=−17⋅(x−3)

y=−17⋅x+37

Jim G.
Jul 18, 2018

y=−17x+37

Explanation:

the equation of a line in slope-intercept form is.

∙xy=mx+b

where m is the slope and b the y-intercept

to calculate m use the gradient formula

∙xm=y2−y1x2−x1

let (x1,y1)=(3,0) and (x2,y2)=(−4,1)

m=1−0−4−3=1−7=−17

y=−17x+b←is the partial equation

to find b substitute either of the 2 given points into
the partial equation

using (3,0) then

0=−37+b⇒b=0+37=37

y=−17x+37←in slope-intercept form

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