What is the slope-intercept form of the line passing through $(4, 5)$ $(4, 5)$ and $(- 4, 1)$ $(-4, 1)$ ?

Question

2520 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-23T15:08:54

You must first find the slope, m.

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m = (y_2 - y_1)/(x_2 - x_1)$

$m = \frac{1 - 5}{- 4 - 4}$ $m = (1 - 5)/(-4 - 4)$

$m = - \frac{4}{- 8}$ $m = -4/-8$

$m = \frac{1}{2}$ $m = 1/2$

Now, using the slope, and one of the points in slope point form,we get:

$y - y_{1} = m (x - x_{1})$ $y - y_1 = m(x - x_1)$

$y - 5 = \frac{1}{2} (x - 4)$ $y - 5 = 1/2(x - 4)$

$y - 5 = \frac{1}{2} x - 2$ $y - 5 = 1/2x - 2$

$y = \frac{1}{2} x + 3$ $y = 1/2x + 3$

Hopefully this helps!

What is the slope-intercept form of the line passing through (4, 5)(4,5)(4, 5) and (-4, 1) (−4,1) (-4, 1) ?