What is the slope-intercept form of the line passing through (-6, 8)(6,8) and (-1, 7) (1,7)?

1 Answer

Slope-intercept form y=mx+by=mx+b is
y=-x/5+34/5y=x5+345

Explanation:

Start from the given. Let P_2(-6, 8)P2(6,8) and P_1(-1, 7)P1(1,7)

from the given , use the two-point form first
y-y_1=((y_2-y_1)/(x_2-x_1))*(x-x_1)yy1=(y2y1x2x1)(xx1)

after which , transform the equation to y=mx+by=mx+b slope-intercept form

y-7=((8-7)/(-6--1))*(x--1)y7=(8761)(x1)

y-7=(1)/(-5)*(x+1)y7=15(x+1)

-5(y-7)=-5(1/-5)*(x+1)5(y7)=5(15)(x+1)

-5(y-7)=cancel(-5)(1/cancel(-5))*(x+1)

-5(y-7)=1*(x+1)

-5y+35=x+1

-5y=x+1-35

-5y=x-34

(-5y)/-5=(x-34)/-5

(cancel(-5)y)/cancel(-5)=(x-34)/-5

y=-x/5+34/5

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