What is the slope intercept form of the line with a slope of $- \frac{5}{4}$ $-5/4$ and y-intercept of $- \frac{2}{3}$ $-2/3$ ?

Question

1966 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-08T11:41:54

$15 x + 12 y + 8 = 0$ $15x+12y+8=0$

The slope intercept form of the line with a slope of $m$ $m$ and and $y$ $y$ -intercept of $c$ $c$ is given by

$y = m x + c$ $y=mx+c$

Hence, slope intercept form of the line with a slope of $- \frac{5}{4}$ $-5/4$ and and $y$ $y$ -intercept of $- \frac{2}{3}$ $-2/3$ is

$y = (- \frac{5}{4}) x + (- \frac{2}{3})$ $y=(-5/4)x+(-2/3)$ and multiplying by $12$ $12$ this becomes

$12 y = 12 \times (- \frac{5}{4}) x + 12 \times (- \frac{2}{3})$ $12y=12xx(-5/4)x+12xx(-2/3)$ or

$12 y = - 15 x - 8$ $12y=-15x-8$

or $15 x + 12 y + 8 = 0$ $15x+12y+8=0$

What is the slope intercept form of the line with a slope of −54-5/4 and y-intercept of −23 -2/3 ?