What is the slope intercept form of the line with a slope of $- \frac{9}{4}$ $-9/4$ and y-intercept of $- \frac{1}{3}$ $-1/3$ ?

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What is the slope intercept form of the line with a slope of $- \frac{9}{4}$ $-9/4$ and y-intercept of $- \frac{1}{3}$ $-1/3$ ?

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Answer 1 · 2018-03-28T09:44:37

$y = \frac{9}{4} x - \frac{1}{3}$ $y=9/4x-1/3$

Explanation:

The general equation of a line is given by: $y - y_{1} = m (x - x_{1})$ $y-y_1=m(x-x_1)$ , where $m$ $m$ is the gradient and $(x_{1}, y_{1})$ $(x_1,y_1)$ are coordinates of a point.

$x = 0$ $x=0$ at the $y$ $y$ -intercept,

$y - - \frac{1}{3} = - \frac{9}{4} (x - 0)$ $y--1/3=-9/4(x-0)$

Expand,

$y + \frac{1}{3} = \frac{9}{4} x$ $y+1/3=9/4x$

Subtract $\frac{1}{3}$ $1/3$ from both sides,

$y = \frac{9}{4} x - \frac{1}{3}$ $y=9/4x-1/3$

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What is the slope intercept form of the line with a slope of $- \frac{9}{4}$ $-9/4$ and y-intercept of $- \frac{1}{3}$ $-1/3$ ?

1 Answer

Explanation:

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What is the slope intercept form of the line with a slope of $- \frac{9}{4}$ $-9/4$ and y-intercept of $- \frac{1}{3}$ $-1/3$ ?