What is the slope of $16y=-80y+140x+39$ ?

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Answer 1 · 2018-04-10T09:16:50

$96y = 140x + 39$

Arrange your equation first:

$y = 140/96x + 39/96$

Your slope is $140/96$

graph{(140/96)x + (39/96) [-10, 10, -5, 5]}

What is the slope of 16y=-80y+140x+3916y=-80y+140x+39?