What is the slope of $7/3y=4/3y-x/4+1$ ?

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Answer 1 · 2018-04-07T00:12:36

The slope is $-1/4$ .

Here's how I did it:

$7/3y = 4/3y - x/4 + 1$

First, let's subtract $4/3y$ from both sides of the equation:
$3/3y = -x/4 + 1$

$y = -x/4 + 1$

Now this equation is written in:
www.katesmathlessons.com

As you can see, the slope is the value in front of the $x$ . In our case, that value is $-1/4$ . Therefore, the slope is $-1/4$ .

Hope this helps!

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