What is the slope of any line perpendicular to the line passing through #(12,-5)# and #(-1,7)#?

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Answer 1 · 2017-03-29T04:34:48

Slope of the perpendicular to the line joining #(12,-5)# and #(-1,7)# is #13/12#

Slope of a line joining #(x_1,y_1)# and #(x_2,y_2)# is

#(y_2-y_1)/(x_2-x_1)#

Therefore slope of line joining #(12,-5)# and #(-1,7)# is

#(7-(-5))/(-1-12)=12/(-13)=-12/13#

As product of slopes of two lines perpendicular to each other is #-1#

slope of the perpendicular to the line joining #(12,-5)# and #(-1,7)# is

#(-1)/(-12/13)=(-1)xx(-13/12)=13/12#