What is the slope of any line perpendicular to the line passing through #(25,-2)# and #(30,34)#?

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Answer 1 · 2016-09-03T00:52:21

Slope of line perpendicular to the one joining #(25,-2)# and #(30,34)# is #-5/36#.

Slope of line joining #(x_1,y_1)# and #(x_2,y_2)# is given by

#(y_2-y_1)/(x_2-x_1)#

Hence slope of line joining #(25,-2)# and #(30,34)# is

#(34-(-2))/(30-25)#

= #36/5#

As the product of slopes of two lines perpendicular to each other is #-1#, slope of line perpendicular to the one joining #(25,-2)# and #(30,34)# is

#-1/(36/5)=-5/36#