What is the slope of the line (-2,8)(-2,-1)?

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What is the slope of the line (-2,8)(-2,-1)?

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Answer 1 · 2016-09-02T03:49:24

The slope is $\infty$ $oo$ and line is vertical and parallel to $y$ $y$ -axis

Explanation:

The slope of a line joining two points $(x_{1}, y_{1})$ $(x_1,y_1)$ and $(x_{2}, y_{2})$ $(x_2,y_2)$ is

$\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $(y_2-y_1)/(x_2-x_1)$

Hence slope of line joining $(- 2, 8)$ $(-2,8)$ and $(- 2, - 1)$ $(-2,-1)$ is

$\frac{- 1 - 8}{- 2 - (- 2)}$ $(-1-8)/(-2-(-2))$

= $- \frac{9}{0} = \infty$ $-9/0=oo$

Hence the line joining $(- 2, 8)$ $(-2,8)$ and $(- 2, - 1)$ $(-2,-1)$ has $\infty$ $oo$ slope i.e. it is perpendicular meaning parallel to $y$ $y$ -axis.

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What is the slope of the line (-2,8)(-2,-1)?

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