What is the slope of the line passing through $(- 3, - 3); (0, 0)$ $(-3,-3); (0,0)$ ?

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What is the slope of the line passing through $(- 3, - 3); (0, 0)$ $(-3,-3); (0,0)$ ?

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Answer 1 · 2018-04-19T06:11:26

The slope is $1$ $1$ . See explanation.

Explanation:

When 2 points on a line $A = (x_{1}; y_{1})$ $A=(x_1;y_1)$ and $B = (x_{2}; y_{2})$ $B=(x_2;y_2)$ are given then the slope of the line passing through the points can be calculated as:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

Here we have:

$m = \frac{0 - (- 3)}{0 - (- 3)} = \frac{0 + 3}{0 + 3} = \frac{3}{3} = 1$ $m=(0-(-3))/(0-(-3))=(0+3)/(0+3)=3/3=1$

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What is the slope of the line passing through $(- 3, - 3); (0, 0)$ $(-3,-3); (0,0)$ ?

1 Answer

Explanation:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$

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What is the slope of the line passing through (-3,-3); (0,0)(−3,−3);(0,0) (-3,-3); (0,0)?

1 Answer

Explanation:

m=(y_2-y_1)/(x_2-x_1)m=y2−y1x2−x1m=(y_2-y_1)/(x_2-x_1)

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Impact of this question

What is the slope of the line passing through $(- 3, - 3); (0, 0)$ $(-3,-3); (0,0)$ ?

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $m=(y_2-y_1)/(x_2-x_1)$